x^2+156x-459=0

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Solution for x^2+156x-459=0 equation:



x^2+156x-459=0
a = 1; b = 156; c = -459;
Δ = b2-4ac
Δ = 1562-4·1·(-459)
Δ = 26172
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{26172}=\sqrt{36*727}=\sqrt{36}*\sqrt{727}=6\sqrt{727}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(156)-6\sqrt{727}}{2*1}=\frac{-156-6\sqrt{727}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(156)+6\sqrt{727}}{2*1}=\frac{-156+6\sqrt{727}}{2} $

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